Poisson Formula Problem



a)      x 3, λ = 4.1

 

Determine each x value from x = 3 on down until the values are so far away from lambda = 4.1 that the probabilities approach zero, which in this case is x = 0. Then sum the result of x = 3, x = 2, x = 1, x = 0.

 

x

λ

P(x)

3

4.1

0.19037

2

4.1

0.13929

1

4.1

0.06795

0

4.1

0.01657

P(x ≤ 3 | λ = 4.1)=

0.41418

 

d) P(x = 0 | λ = 2.7)

 

 

 

 

 

 

 

 

 

 

 

 

 

 


       e) P(x = 1 | λ = 5.4)